Base | Representation |
---|---|
bin | 1100101111011111110010… |
… | …0001111011110011000011 |
3 | 1211121100120201002122120012 |
4 | 3023313330201323303003 |
5 | 3314020214011400441 |
6 | 45444055043135135 |
7 | 2644124650342112 |
oct | 313677441736303 |
9 | 54540521078505 |
10 | 14010125106371 |
11 | 451172a419999 |
12 | 16a330a6744ab |
13 | 7a81c2835654 |
14 | 366145079c79 |
15 | 19467ec6e9eb |
hex | cbdfc87bcc3 |
14010125106371 has 2 divisors, whose sum is σ = 14010125106372. Its totient is φ = 14010125106370.
The previous prime is 14010125106353. The next prime is 14010125106449. The reversal of 14010125106371 is 17360152101041.
It is a weak prime.
It is an emirp because it is prime and its reverse (17360152101041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14010125106371 - 218 = 14010124844227 is a prime.
It is not a weakly prime, because it can be changed into another prime (14010125106871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005062553185 + 7005062553186.
It is an arithmetic number, because the mean of its divisors is an integer number (7005062553186).
Almost surely, 214010125106371 is an apocalyptic number.
14010125106371 is a deficient number, since it is larger than the sum of its proper divisors (1).
14010125106371 is an equidigital number, since it uses as much as digits as its factorization.
14010125106371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 32.
The spelling of 14010125106371 in words is "fourteen trillion, ten billion, one hundred twenty-five million, one hundred six thousand, three hundred seventy-one".
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