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1401031312003 = 9710314428301
BaseRepresentation
bin10100011000110011111…
…110010100001010000011
311221221022021120212120201
4110120303332110022003
5140423303003441003
62551342551150031
7203135601442411
oct24306376241203
94857267525521
101401031312003
114a01a0718264
121a7642675317
13a216948826b
144bb4b5882b1
152669d978b1d
hex14633f94283

1401031312003 has 4 divisors (see below), whose sum is σ = 1401045837408. Its totient is φ = 1401016786600.

The previous prime is 1401031311991. The next prime is 1401031312039. The reversal of 1401031312003 is 3002131301041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1401031312003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1401031315003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7117048 + ... + 7311253.

It is an arithmetic number, because the mean of its divisors is an integer number (350261459352).

Almost surely, 21401031312003 is an apocalyptic number.

1401031312003 is a deficient number, since it is larger than the sum of its proper divisors (14525405).

1401031312003 is an equidigital number, since it uses as much as digits as its factorization.

1401031312003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14525404.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1401031312003 its reverse (3002131301041), we get a palindrome (4403162613044).

The spelling of 1401031312003 in words is "one trillion, four hundred one billion, thirty-one million, three hundred twelve thousand, three".

Divisors: 1 97103 14428301 1401031312003