140104043151313 has 4 divisors (see below), whose sum is σ = 140519782152100. Its totient is φ = 139688304150528.

The previous prime is 140104043151239. The next prime is 140104043151349. The reversal of 140104043151313 is 313151340401041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 88037254855489 + 52066788295824 = 9382817^2 + 7215732^2 .

It is a cyclic number.

It is not a de Polignac number, because 140104043151313 - 2¹³ = 140104043143121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140104043151383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 207869499888 + ... + 207869500561.

It is an arithmetic number, because the mean of its divisors is an integer number (35129945538025).

Almost surely, 2^{140104043151313} is an apocalyptic number.

It is an amenable number.

140104043151313 is a deficient number, since it is larger than the sum of its proper divisors (415739000787).

140104043151313 is an equidigital number, since it uses as much as digits as its factorization.

140104043151313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 415739000786.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 140104043151313 its reverse (313151340401041), we get a palindrome (453255383552354).

The spelling of 140104043151313 in words is "one hundred forty trillion, one hundred four billion, forty-three million, one hundred fifty-one thousand, three hundred thirteen".