Base | Representation |
---|---|
bin | 11010000110001011… |
… | …00110101000010011 |
3 | 1100011102010022110201 |
4 | 31003011212220103 |
5 | 212143133204212 |
6 | 10234124240031 |
7 | 1004122545256 |
oct | 150305465023 |
9 | 40142108421 |
10 | 14010444307 |
11 | 5a3a5921a2 |
12 | 28700a0017 |
13 | 1423827a42 |
14 | 96ca3509d |
15 | 56eee7b57 |
hex | 343166a13 |
14010444307 has 2 divisors, whose sum is σ = 14010444308. Its totient is φ = 14010444306.
The previous prime is 14010444299. The next prime is 14010444323. The reversal of 14010444307 is 70344401041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14010444307 - 23 = 14010444299 is a prime.
It is not a weakly prime, because it can be changed into another prime (14010444377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005222153 + 7005222154.
It is an arithmetic number, because the mean of its divisors is an integer number (7005222154).
Almost surely, 214010444307 is an apocalyptic number.
14010444307 is a deficient number, since it is larger than the sum of its proper divisors (1).
14010444307 is an equidigital number, since it uses as much as digits as its factorization.
14010444307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5376, while the sum is 28.
Adding to 14010444307 its reverse (70344401041), we get a palindrome (84354845348).
The spelling of 14010444307 in words is "fourteen billion, ten million, four hundred forty-four thousand, three hundred seven".
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