1401103617553 has 4 divisors (see below), whose sum is σ = 1401113968128. Its totient is φ = 1401093266980.

The previous prime is 1401103617541. The next prime is 1401103617581. The reversal of 1401103617553 is 3557163011041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1401103617553 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1401103617503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4969513 + ... + 5243878.

It is an arithmetic number, because the mean of its divisors is an integer number (350278492032).

Almost surely, 2^{1401103617553} is an apocalyptic number.

It is an amenable number.

1401103617553 is a deficient number, since it is larger than the sum of its proper divisors (10350575).

1401103617553 is a wasteful number, since it uses less digits than its factorization.

1401103617553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10350574.

The product of its (nonzero) digits is 37800, while the sum is 37.

Adding to 1401103617553 its reverse (3557163011041), we get a palindrome (4958266628594).

The spelling of 1401103617553 in words is "one trillion, four hundred one billion, one hundred three million, six hundred seventeen thousand, five hundred fifty-three".