14011050441 has 4 divisors (see below), whose sum is σ = 18681400592. Its totient is φ = 9340700292.

The previous prime is 14011050379. The next prime is 14011050491. The reversal of 14011050441 is 14405011041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14405011041 = 3 ⋅4801670347.

It is not a de Polignac number, because 14011050441 - 2⁹ = 14011049929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14011050491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2335175071 + ... + 2335175076.

It is an arithmetic number, because the mean of its divisors is an integer number (4670350148).

Almost surely, 2^14011050441 is an apocalyptic number.

It is an amenable number.

14011050441 is a deficient number, since it is larger than the sum of its proper divisors (4670350151).

14011050441 is an equidigital number, since it uses as much as digits as its factorization.

14011050441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4670350150.

The product of its (nonzero) digits is 320, while the sum is 21.

Adding to 14011050441 its reverse (14405011041), we get a palindrome (28416061482).

The spelling of 14011050441 in words is "fourteen billion, eleven million, fifty thousand, four hundred forty-one".