14011051441 has 4 divisors (see below), whose sum is σ = 14011353712. Its totient is φ = 14010749172.

The previous prime is 14011051429. The next prime is 14011051451. The reversal of 14011051441 is 14415011041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14011051441 - 2¹⁷ = 14010920369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14011051451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65391 + ... + 179716.

It is an arithmetic number, because the mean of its divisors is an integer number (3502838428).

Almost surely, 2^14011051441 is an apocalyptic number.

It is an amenable number.

14011051441 is a deficient number, since it is larger than the sum of its proper divisors (302271).

14011051441 is an equidigital number, since it uses as much as digits as its factorization.

14011051441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 302270.

The product of its (nonzero) digits is 320, while the sum is 22.

Adding to 14011051441 its reverse (14415011041), we get a palindrome (28426062482).

The spelling of 14011051441 in words is "fourteen billion, eleven million, fifty-one thousand, four hundred forty-one".