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1401121040041 is a prime number
BaseRepresentation
bin10100011000111001010…
…100100110011010101001
311221221112112102112022101
4110120321110212122221
5140423443441240131
62551355514253401
7203141041223242
oct24307124463251
94857475375271
101401121040041
114a0237333268
121a7668727261
13a2181c43488
144bb59463cc9
15266a679ec61
hex146395266a9

1401121040041 has 2 divisors, whose sum is σ = 1401121040042. Its totient is φ = 1401121040040.

The previous prime is 1401121040003. The next prime is 1401121040057. The reversal of 1401121040041 is 1400401211041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1397301305625 + 3819734416 = 1182075^2 + 61804^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1401121040041 is a prime.

It is not a weakly prime, because it can be changed into another prime (1401121040071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700560520020 + 700560520021.

It is an arithmetic number, because the mean of its divisors is an integer number (700560520021).

Almost surely, 21401121040041 is an apocalyptic number.

It is an amenable number.

1401121040041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401121040041 is an equidigital number, since it uses as much as digits as its factorization.

1401121040041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 128, while the sum is 19.

Adding to 1401121040041 its reverse (1400401211041), we get a palindrome (2801522251082).

The spelling of 1401121040041 in words is "one trillion, four hundred one billion, one hundred twenty-one million, forty thousand, forty-one".