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14011303210441 = 73531473611411
BaseRepresentation
bin1100101111100100001011…
…0000000010110111001001
31211121110121210220112112021
43023321002300002313021
53314030122110213231
645444412010044441
72644166104143625
oct313710260026711
954543553815467
1014011303210441
11451218442aa19
1216a3599119721
137a834c931754
1436621770a185
151946ed3d2811
hexcbe42c02dc9

14011303210441 has 8 divisors (see below), whose sum is σ = 14203510048224. Its totient is φ = 13819103701920.

The previous prime is 14011303210417. The next prime is 14011303210453. The reversal of 14011303210441 is 14401230311041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14011303210441 - 29 = 14011303209929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14011303510441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2074026 + ... + 5685436.

It is an arithmetic number, because the mean of its divisors is an integer number (1775438756028).

Almost surely, 214011303210441 is an apocalyptic number.

It is an amenable number.

14011303210441 is a deficient number, since it is larger than the sum of its proper divisors (192206837783).

14011303210441 is an equidigital number, since it uses as much as digits as its factorization.

14011303210441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3664631.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14011303210441 its reverse (14401230311041), we get a palindrome (28412533521482).

The spelling of 14011303210441 in words is "fourteen trillion, eleven billion, three hundred three million, two hundred ten thousand, four hundred forty-one".

Divisors: 1 73 53147 3611411 3879731 263633003 191935660417 14011303210441