Base | Representation |
---|---|
bin | 1100101111100100001011… |
… | …0000000111111101100010 |
3 | 1211121110121210221121011221 |
4 | 3023321002300013331202 |
5 | 3314030122111400310 |
6 | 45444412010325254 |
7 | 2644166104261546 |
oct | 313710260077542 |
9 | 54543553847157 |
10 | 14011303231330 |
11 | 4512184444689 |
12 | 16a359912982a |
13 | 7a834c93b102 |
14 | 366217713a26 |
15 | 1946ed3d8ada |
hex | cbe42c07f62 |
14011303231330 has 32 divisors (see below), whose sum is σ = 25238204006400. Its totient is φ = 5600553596352.
The previous prime is 14011303231309. The next prime is 14011303231369. The reversal of 14011303231330 is 3313230311041.
14011303231330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 14011303231295 and 14011303231304.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 159758431 + ... + 159846109.
It is an arithmetic number, because the mean of its divisors is an integer number (788693875200).
Almost surely, 214011303231330 is an apocalyptic number.
14011303231330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14011303231330 is a deficient number, since it is larger than the sum of its proper divisors (11226900775070).
14011303231330 is a wasteful number, since it uses less digits than its factorization.
14011303231330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98818.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 14011303231330 its reverse (3313230311041), we get a palindrome (17324533542371).
The spelling of 14011303231330 in words is "fourteen trillion, eleven billion, three hundred three million, two hundred thirty-one thousand, three hundred thirty".
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