Base | Representation |
---|---|
bin | 1100101111100100001011… |
… | …0000011001110100101011 |
3 | 1211121110121211002022112121 |
4 | 3023321002300121310223 |
5 | 3314030122121220431 |
6 | 45444412012052111 |
7 | 2644166105015053 |
oct | 313710260316453 |
9 | 54543554068477 |
10 | 14011303304491 |
11 | 4512184494649 |
12 | 16a3599164037 |
13 | 7a834c9654bc |
14 | 366217732563 |
15 | 1946ed400611 |
hex | cbe42c19d2b |
14011303304491 has 2 divisors, whose sum is σ = 14011303304492. Its totient is φ = 14011303304490.
The previous prime is 14011303304359. The next prime is 14011303304497. The reversal of 14011303304491 is 19440330311041.
14011303304491 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14011303304491 - 219 = 14011302780203 is a prime.
It is not a weakly prime, because it can be changed into another prime (14011303304497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005651652245 + 7005651652246.
It is an arithmetic number, because the mean of its divisors is an integer number (7005651652246).
Almost surely, 214011303304491 is an apocalyptic number.
14011303304491 is a deficient number, since it is larger than the sum of its proper divisors (1).
14011303304491 is an equidigital number, since it uses as much as digits as its factorization.
14011303304491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 14011303304491 in words is "fourteen trillion, eleven billion, three hundred three million, three hundred four thousand, four hundred ninety-one".
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