Base | Representation |
---|---|
bin | 1100101111100100001011… |
… | …0011011100101000000011 |
3 | 1211121110121212120212001220 |
4 | 3023321002303130220003 |
5 | 3314030122322234103 |
6 | 45444412041130123 |
7 | 2644166114550246 |
oct | 313710263345003 |
9 | 54543555525056 |
10 | 14011304102403 |
11 | 451218498a083 |
12 | 16a3599489943 |
13 | 7a834cb8473a |
14 | 36621789d25d |
15 | 1946ed50bc53 |
hex | cbe42cdca03 |
14011304102403 has 4 divisors (see below), whose sum is σ = 18681738803208. Its totient is φ = 9340869401600.
The previous prime is 14011304102381. The next prime is 14011304102429. The reversal of 14011304102403 is 30420140311041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14011304102403 - 29 = 14011304101891 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14011304102203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2335217350398 + ... + 2335217350403.
It is an arithmetic number, because the mean of its divisors is an integer number (4670434700802).
Almost surely, 214011304102403 is an apocalyptic number.
14011304102403 is a deficient number, since it is larger than the sum of its proper divisors (4670434700805).
14011304102403 is an equidigital number, since it uses as much as digits as its factorization.
14011304102403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4670434700804.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 14011304102403 its reverse (30420140311041), we get a palindrome (44431444413444).
The spelling of 14011304102403 in words is "fourteen trillion, eleven billion, three hundred four million, one hundred two thousand, four hundred three".
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