140113102034401 has 4 divisors (see below), whose sum is σ = 140114206814400. Its totient is φ = 140111997254404.

The previous prime is 140113102034341. The next prime is 140113102034407. The reversal of 140113102034401 is 104430201311041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140113102034401 - 2³¹ = 140110954550753 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140113102034407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 552199741 + ... + 552453418.

It is an arithmetic number, because the mean of its divisors is an integer number (35028551703600).

Almost surely, 2^{140113102034401} is an apocalyptic number.

It is an amenable number.

140113102034401 is a deficient number, since it is larger than the sum of its proper divisors (1104779999).

140113102034401 is a wasteful number, since it uses less digits than its factorization.

140113102034401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1104779998.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 140113102034401 its reverse (104430201311041), we get a palindrome (244543303345442).

The spelling of 140113102034401 in words is "one hundred forty trillion, one hundred thirteen billion, one hundred two million, thirty-four thousand, four hundred one".