Base | Representation |
---|---|
bin | 1100101111100100001101… |
… | …0101100110011101000010 |
3 | 1211121110122111102201111002 |
4 | 3023321003111212131002 |
5 | 3314030132120234204 |
6 | 45444413001052002 |
7 | 2644166253626603 |
oct | 313710325463502 |
9 | 54543574381432 |
10 | 14011313055554 |
11 | 4512189a44781 |
12 | 16a35a0487002 |
13 | 7a835199a969 |
14 | 366218b4ddaa |
15 | 1946ee1c991e |
hex | cbe43566742 |
14011313055554 has 4 divisors (see below), whose sum is σ = 21016969583334. Its totient is φ = 7005656527776.
The previous prime is 14011313055547. The next prime is 14011313055581. The reversal of 14011313055554 is 45555031311041.
14011313055554 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 7147725231529 + 6863587824025 = 2673523^2 + 2619845^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3502828263887 + ... + 3502828263890.
Almost surely, 214011313055554 is an apocalyptic number.
14011313055554 is a deficient number, since it is larger than the sum of its proper divisors (7005656527780).
14011313055554 is an equidigital number, since it uses as much as digits as its factorization.
14011313055554 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7005656527779.
The product of its (nonzero) digits is 90000, while the sum is 38.
Adding to 14011313055554 its reverse (45555031311041), we get a palindrome (59566344366595).
The spelling of 14011313055554 in words is "fourteen trillion, eleven billion, three hundred thirteen million, fifty-five thousand, five hundred fifty-four".
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