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140113134251 is a prime number
BaseRepresentation
bin1000001001111101100…
…1001100001010101011
3111101122201120200202122
42002133121030022223
54243422430244001
6144211142421455
713060063663526
oct2023731141253
9441581520678
10140113134251
1154470236622
12231a373188b
131029c153b3c
146ad267bbbd
1539a0b1cb1b
hex209f64c2ab

140113134251 has 2 divisors, whose sum is σ = 140113134252. Its totient is φ = 140113134250.

The previous prime is 140113134221. The next prime is 140113134257. The reversal of 140113134251 is 152431311041.

It is a strong prime.

It is an emirp because it is prime and its reverse (152431311041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140113134251 - 234 = 122933265067 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 140113134251.

It is not a weakly prime, because it can be changed into another prime (140113134257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70056567125 + 70056567126.

It is an arithmetic number, because the mean of its divisors is an integer number (70056567126).

Almost surely, 2140113134251 is an apocalyptic number.

140113134251 is a deficient number, since it is larger than the sum of its proper divisors (1).

140113134251 is an equidigital number, since it uses as much as digits as its factorization.

140113134251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 140113134251 its reverse (152431311041), we get a palindrome (292544445292).

The spelling of 140113134251 in words is "one hundred forty billion, one hundred thirteen million, one hundred thirty-four thousand, two hundred fifty-one".