Base | Representation |
---|---|
bin | 1100101111100100001111… |
… | …0100011000011001010010 |
3 | 1211121110200001121122220111 |
4 | 3023321003310120121102 |
5 | 3314030141201440214 |
6 | 45444413450031534 |
7 | 2644166412334204 |
oct | 313710364303122 |
9 | 54543601548814 |
10 | 14011321124434 |
11 | 4512193555a77 |
12 | 16a35a31185aa |
13 | 7a835356454a |
14 | 366219c50774 |
15 | 1946eec705c4 |
hex | cbe43d18652 |
14011321124434 has 8 divisors (see below), whose sum is σ = 21283019429760. Its totient is φ = 6916981314516.
The previous prime is 14011321124419. The next prime is 14011321124443. The reversal of 14011321124434 is 43442112311041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×140113211244342 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14011321124396 and 14011321124405.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44339623654 + ... + 44339623969.
It is an arithmetic number, because the mean of its divisors is an integer number (2660377428720).
Almost surely, 214011321124434 is an apocalyptic number.
14011321124434 is a deficient number, since it is larger than the sum of its proper divisors (7271698305326).
14011321124434 is an equidigital number, since it uses as much as digits as its factorization.
14011321124434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 88679247704.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 14011321124434 its reverse (43442112311041), we get a palindrome (57453433435475).
The spelling of 14011321124434 in words is "fourteen trillion, eleven billion, three hundred twenty-one million, one hundred twenty-four thousand, four hundred thirty-four".
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