1401134213041 has 2 divisors, whose sum is σ = 1401134213042. Its totient is φ = 1401134213040.

The previous prime is 1401134212987. The next prime is 1401134213053. The reversal of 1401134213041 is 1403124311041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1089654138225 + 311480074816 = 1043865^2 + 558104^2 .

It is a cyclic number.

It is not a de Polignac number, because 1401134213041 - 2²³ = 1401125824433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1401134212997 and 1401134213015.

It is not a weakly prime, because it can be changed into another prime (1401134213741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700567106520 + 700567106521.

It is an arithmetic number, because the mean of its divisors is an integer number (700567106521).

Almost surely, 2^{1401134213041} is an apocalyptic number.

It is an amenable number.

1401134213041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401134213041 is an equidigital number, since it uses as much as digits as its factorization.

1401134213041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1401134213041 its reverse (1403124311041), we get a palindrome (2804258524082).

The spelling of 1401134213041 in words is "one trillion, four hundred one billion, one hundred thirty-four million, two hundred thirteen thousand, forty-one".