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140121005502433 is a prime number
BaseRepresentation
bin11111110111000001110110…
…110000100010111111100001
3200101010102210210102222010111
4133313001312300202333201
5121331220304402034213
61214002411250531321
741341260066060334
oct3767016660427741
9611112723388114
10140121005502433
1140712a9172820a
1213870481296b41
13602547b010607
142685c6ddb461b
15112ed078ada3d
hex7f7076c22fe1

140121005502433 has 2 divisors, whose sum is σ = 140121005502434. Its totient is φ = 140121005502432.

The previous prime is 140121005502389. The next prime is 140121005502437. The reversal of 140121005502433 is 334205500121041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72757095669729 + 67363909832704 = 8529777^2 + 8207552^2 .

It is a cyclic number.

It is not a de Polignac number, because 140121005502433 - 237 = 139983566548961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140121005502395 and 140121005502404.

It is not a weakly prime, because it can be changed into another prime (140121005502437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70060502751216 + 70060502751217.

It is an arithmetic number, because the mean of its divisors is an integer number (70060502751217).

Almost surely, 2140121005502433 is an apocalyptic number.

It is an amenable number.

140121005502433 is a deficient number, since it is larger than the sum of its proper divisors (1).

140121005502433 is an equidigital number, since it uses as much as digits as its factorization.

140121005502433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 140121005502433 its reverse (334205500121041), we get a palindrome (474326505623474).

The spelling of 140121005502433 in words is "one hundred forty trillion, one hundred twenty-one billion, five million, five hundred two thousand, four hundred thirty-three".