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14012132234203 = 85223164417261
BaseRepresentation
bin1100101111100111010000…
…1010100001001111011011
31211121112202120212022100001
43023321310022201033123
53314033321322443303
645445030142553431
72644225461551545
oct313716412411733
954545676768301
1014012132234203
11451256a394824
1216a378a898877
137a845260715c
1436629586c695
1519474b08e31d
hexcbe742a13db

14012132234203 has 4 divisors (see below), whose sum is σ = 14012296736688. Its totient is φ = 14011967731720.

The previous prime is 14012132234171. The next prime is 14012132234207. The reversal of 14012132234203 is 30243223121041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14012132234203 - 25 = 14012132234171 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14012132234207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82123408 + ... + 82293853.

It is an arithmetic number, because the mean of its divisors is an integer number (3503074184172).

Almost surely, 214012132234203 is an apocalyptic number.

14012132234203 is a deficient number, since it is larger than the sum of its proper divisors (164502485).

14012132234203 is an equidigital number, since it uses as much as digits as its factorization.

14012132234203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 164502484.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 14012132234203 its reverse (30243223121041), we get a palindrome (44255355355244).

The spelling of 14012132234203 in words is "fourteen trillion, twelve billion, one hundred thirty-two million, two hundred thirty-four thousand, two hundred three".

Divisors: 1 85223 164417261 14012132234203