140122330013131 has 4 divisors (see below), whose sum is σ = 140122876234264. Its totient is φ = 140121783792000.

The previous prime is 140122330013053. The next prime is 140122330013161. The reversal of 140122330013131 is 131310033221041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140122330013131 - 2¹⁵ = 140122329980363 is a prime.

It is a super-2 number, since 2×140122330013131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140122330013096 and 140122330013105.

It is not an unprimeable number, because it can be changed into a prime (140122330013161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 272725590 + ... + 273238891.

It is an arithmetic number, because the mean of its divisors is an integer number (35030719058566).

Almost surely, 2^{140122330013131} is an apocalyptic number.

140122330013131 is a deficient number, since it is larger than the sum of its proper divisors (546221133).

140122330013131 is an equidigital number, since it uses as much as digits as its factorization.

140122330013131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 546221132.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 140122330013131 its reverse (131310033221041), we get a palindrome (271432363234172).

The spelling of 140122330013131 in words is "one hundred forty trillion, one hundred twenty-two billion, three hundred thirty million, thirteen thousand, one hundred thirty-one".