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14012300023003 = 131106964122313
BaseRepresentation
bin1100101111100111111000…
…1010100101010011011011
31211121120012021120212022001
43023321332022211103123
53314034142301214003
645445054535141431
72644232600000662
oct313717612452333
954546167525261
1014012300023003
114512646076a57
1216a3816b14877
137a847b2c3b79
143662adc67dd9
1519475ab8461d
hexcbe7e2a54db

14012300023003 has 4 divisors (see below), whose sum is σ = 14119264145448. Its totient is φ = 13905335900560.

The previous prime is 14012300022989. The next prime is 14012300023013. The reversal of 14012300023003 is 30032000321041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14012300023003 - 221 = 14012297925851 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14012300023013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53482061026 + ... + 53482061287.

It is an arithmetic number, because the mean of its divisors is an integer number (3529816036362).

Almost surely, 214012300023003 is an apocalyptic number.

14012300023003 is a deficient number, since it is larger than the sum of its proper divisors (106964122445).

14012300023003 is a wasteful number, since it uses less digits than its factorization.

14012300023003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106964122444.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 14012300023003 its reverse (30032000321041), we get a palindrome (44044300344044).

The spelling of 14012300023003 in words is "fourteen trillion, twelve billion, three hundred million, twenty-three thousand, three".

Divisors: 1 131 106964122313 14012300023003