1401231414433 has 8 divisors (see below), whose sum is σ = 1439588337408. Its totient is φ = 1362900060144.

The previous prime is 1401231414421. The next prime is 1401231414437. The reversal of 1401231414433 is 3344141321041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1401231414433 is a prime.

It is a super-2 number, since 2×1401231414433² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1401231414395 and 1401231414404.

It is not an unprimeable number, because it can be changed into a prime (1401231414437) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6281041 + ... + 6500302.

It is an arithmetic number, because the mean of its divisors is an integer number (179948542176).

Almost surely, 2^{1401231414433} is an apocalyptic number.

It is an amenable number.

1401231414433 is a deficient number, since it is larger than the sum of its proper divisors (38356922975).

1401231414433 is a wasteful number, since it uses less digits than its factorization.

1401231414433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12784343.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1401231414433 its reverse (3344141321041), we get a palindrome (4745372735474).

The spelling of 1401231414433 in words is "one trillion, four hundred one billion, two hundred thirty-one million, four hundred fourteen thousand, four hundred thirty-three".