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1401243913 is a prime number
BaseRepresentation
bin101001110000101…
…0100100100001001
310121122200120021201
41103201110210021
510332204301123
6351013304201
746503243136
oct12341244411
93548616251
101401243913
11659a69323
12331335061
131943c5a14
14d415758d
158303d5ad
hex53854909

1401243913 has 2 divisors, whose sum is σ = 1401243914. Its totient is φ = 1401243912.

The previous prime is 1401243869. The next prime is 1401243929. The reversal of 1401243913 is 3193421041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1217451664 + 183792249 = 34892^2 + 13557^2 .

It is an emirp because it is prime and its reverse (3193421041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1401243913 is a prime.

It is not a weakly prime, because it can be changed into another prime (1401243013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700621956 + 700621957.

It is an arithmetic number, because the mean of its divisors is an integer number (700621957).

Almost surely, 21401243913 is an apocalyptic number.

It is an amenable number.

1401243913 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401243913 is an equidigital number, since it uses as much as digits as its factorization.

1401243913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 28.

The square root of 1401243913 is about 37433.1926637309. The cubic root of 1401243913 is about 1119.0201658399.

Adding to 1401243913 its reverse (3193421041), we get a palindrome (4594664954).

The spelling of 1401243913 in words is "one billion, four hundred one million, two hundred forty-three thousand, nine hundred thirteen".