Base | Representation |
---|---|
bin | 101001110000101… |
… | …0100100100001001 |
3 | 10121122200120021201 |
4 | 1103201110210021 |
5 | 10332204301123 |
6 | 351013304201 |
7 | 46503243136 |
oct | 12341244411 |
9 | 3548616251 |
10 | 1401243913 |
11 | 659a69323 |
12 | 331335061 |
13 | 1943c5a14 |
14 | d415758d |
15 | 8303d5ad |
hex | 53854909 |
1401243913 has 2 divisors, whose sum is σ = 1401243914. Its totient is φ = 1401243912.
The previous prime is 1401243869. The next prime is 1401243929. The reversal of 1401243913 is 3193421041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1217451664 + 183792249 = 34892^2 + 13557^2 .
It is an emirp because it is prime and its reverse (3193421041) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1401243913 is a prime.
It is not a weakly prime, because it can be changed into another prime (1401243013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700621956 + 700621957.
It is an arithmetic number, because the mean of its divisors is an integer number (700621957).
Almost surely, 21401243913 is an apocalyptic number.
It is an amenable number.
1401243913 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401243913 is an equidigital number, since it uses as much as digits as its factorization.
1401243913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 28.
The square root of 1401243913 is about 37433.1926637309. The cubic root of 1401243913 is about 1119.0201658399.
Adding to 1401243913 its reverse (3193421041), we get a palindrome (4594664954).
The spelling of 1401243913 in words is "one billion, four hundred one million, two hundred forty-three thousand, nine hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •