Base | Representation |
---|---|
bin | 11111110111001010011101… |
… | …100110110101001001010011 |
3 | 200101011022122212022220202001 |
4 | 133313022131212311021103 |
5 | 121331343221240420423 |
6 | 1214010540304334431 |
7 | 41342035105161106 |
oct | 3767123546651123 |
9 | 611138585286661 |
10 | 140130247201363 |
11 | 407169a43a2421 |
12 | 13872220314417 |
13 | 60262c1887b13 |
14 | 26864a954473d |
15 | 1130198dcecad |
hex | 7f729d9b5253 |
140130247201363 has 2 divisors, whose sum is σ = 140130247201364. Its totient is φ = 140130247201362.
The previous prime is 140130247201279. The next prime is 140130247201369. The reversal of 140130247201363 is 363102742031041.
It is a strong prime.
It is an emirp because it is prime and its reverse (363102742031041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 140130247201363 - 217 = 140130247070291 is a prime.
It is not a weakly prime, because it can be changed into another prime (140130247201369) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70065123600681 + 70065123600682.
It is an arithmetic number, because the mean of its divisors is an integer number (70065123600682).
Almost surely, 2140130247201363 is an apocalyptic number.
140130247201363 is a deficient number, since it is larger than the sum of its proper divisors (1).
140130247201363 is an equidigital number, since it uses as much as digits as its factorization.
140130247201363 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 37.
The spelling of 140130247201363 in words is "one hundred forty trillion, one hundred thirty billion, two hundred forty-seven million, two hundred one thousand, three hundred sixty-three".
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