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14013040201 = 106871311223
BaseRepresentation
bin11010000110011111…
…00000011001001001
31100011121000012100221
431003033200121021
5212144314241301
610234300030041
71004153606416
oct150317403111
940147005327
1014013040201
115a40aa5566
122870b32321
131424226484
1496d10d10d
1557035bda1
hex3433e0649

14013040201 has 4 divisors (see below), whose sum is σ = 14014362112. Its totient is φ = 14011718292.

The previous prime is 14013040159. The next prime is 14013040219. The reversal of 14013040201 is 10204031041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10204031041 = 33913009151.

It is a cyclic number.

It is not a de Polignac number, because 14013040201 - 213 = 14013032009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14013040291) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 644925 + ... + 666298.

It is an arithmetic number, because the mean of its divisors is an integer number (3503590528).

Almost surely, 214013040201 is an apocalyptic number.

It is an amenable number.

14013040201 is a deficient number, since it is larger than the sum of its proper divisors (1321911).

14013040201 is a wasteful number, since it uses less digits than its factorization.

14013040201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1321910.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 14013040201 its reverse (10204031041), we get a palindrome (24217071242).

The spelling of 14013040201 in words is "fourteen billion, thirteen million, forty thousand, two hundred one".

Divisors: 1 10687 1311223 14013040201