Base | Representation |
---|---|
bin | 1100101111101010101001… |
… | …0101100111110101001010 |
3 | 1211121122002221002012122010 |
4 | 3023322222111213311022 |
5 | 3314042202011130232 |
6 | 45445300251240350 |
7 | 2644260136114266 |
oct | 313725225476512 |
9 | 54548087065563 |
10 | 14013041114442 |
11 | 4512996431a17 |
12 | 16a39a31490b6 |
13 | 7a85689bc806 |
14 | 36634045b0a6 |
15 | 1947a0c720cc |
hex | cbeaa567d4a |
14013041114442 has 32 divisors (see below), whose sum is σ = 28341060959232. Its totient is φ = 4618605855744.
The previous prime is 14013041114417. The next prime is 14013041114459. The reversal of 14013041114442 is 24441114031041.
It is a super-3 number, since 3×140130411144423 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10442523 + ... + 11707790.
It is an arithmetic number, because the mean of its divisors is an integer number (885658154976).
Almost surely, 214013041114442 is an apocalyptic number.
14013041114442 is an abundant number, since it is smaller than the sum of its proper divisors (14328019844790).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14013041114442 is a wasteful number, since it uses less digits than its factorization.
14013041114442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22151502.
The product of its (nonzero) digits is 6144, while the sum is 30.
Adding to 14013041114442 its reverse (24441114031041), we get a palindrome (38454155145483).
The spelling of 14013041114442 in words is "fourteen trillion, thirteen billion, forty-one million, one hundred fourteen thousand, four hundred forty-two".
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