14013101124001 has 4 divisors (see below), whose sum is σ = 16014972713152. Its totient is φ = 12011229534852.

The previous prime is 14013101123969. The next prime is 14013101124017. The reversal of 14013101124001 is 10042110131041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14013101124001 - 2⁵ = 14013101123969 is a prime.

It is a super-2 number, since 2×14013101124001² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14013101124001.

It is not an unprimeable number, because it can be changed into a prime (14013101124041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1000935794565 + ... + 1000935794578.

It is an arithmetic number, because the mean of its divisors is an integer number (4003743178288).

Almost surely, 2^{14013101124001} is an apocalyptic number.

It is an amenable number.

14013101124001 is a deficient number, since it is larger than the sum of its proper divisors (2001871589151).

14013101124001 is an equidigital number, since it uses as much as digits as its factorization.

14013101124001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2001871589150.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 14013101124001 its reverse (10042110131041), we get a palindrome (24055211255042).

The spelling of 14013101124001 in words is "fourteen trillion, thirteen billion, one hundred one million, one hundred twenty-four thousand, one".