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1401314024113 is a prime number
BaseRepresentation
bin10100011001000100110…
…100110001101010110001
311221222000222120010200121
4110121010310301222301
5140424342342232423
62551431010450241
7203145603450103
oct24310464615261
94858028503617
101401314024113
114a0326264033
121a7701293981
13a21b2c12233
144bb76d3b573
15266b86c045d
hex14644d31ab1

1401314024113 has 2 divisors, whose sum is σ = 1401314024114. Its totient is φ = 1401314024112.

The previous prime is 1401314024057. The next prime is 1401314024137. The reversal of 1401314024113 is 3114204131041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1359702919969 + 41611104144 = 1166063^2 + 203988^2 .

It is a cyclic number.

It is not a de Polignac number, because 1401314024113 - 29 = 1401314023601 is a prime.

It is not a weakly prime, because it can be changed into another prime (1401314024213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700657012056 + 700657012057.

It is an arithmetic number, because the mean of its divisors is an integer number (700657012057).

Almost surely, 21401314024113 is an apocalyptic number.

It is an amenable number.

1401314024113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401314024113 is an equidigital number, since it uses as much as digits as its factorization.

1401314024113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1401314024113 its reverse (3114204131041), we get a palindrome (4515518155154).

The spelling of 1401314024113 in words is "one trillion, four hundred one billion, three hundred fourteen million, twenty-four thousand, one hundred thirteen".