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1401314112403 = 19127580735231
BaseRepresentation
bin10100011001000100110…
…101000111001110010011
311221222000222201121210121
4110121010311013032103
5140424342403044103
62551431012411111
7203145604265362
oct24310465071623
94858028647717
101401314112403
114a03263143a7
121a7701316a97
13a21b2c4348a
144bb76d617d9
15266b86db6bd
hex14644d47393

1401314112403 has 8 divisors (see below), whose sum is σ = 1486682193920. Its totient is φ = 1317107501640.

The previous prime is 1401314112391. The next prime is 1401314112413. The reversal of 1401314112403 is 3042114131041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1401314112403 - 229 = 1400777241491 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1401314112413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 290365203 + ... + 290370028.

It is an arithmetic number, because the mean of its divisors is an integer number (185835274240).

Almost surely, 21401314112403 is an apocalyptic number.

1401314112403 is a deficient number, since it is larger than the sum of its proper divisors (85368081517).

1401314112403 is a wasteful number, since it uses less digits than its factorization.

1401314112403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 580735377.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1401314112403 its reverse (3042114131041), we get a palindrome (4443428243444).

The spelling of 1401314112403 in words is "one trillion, four hundred one billion, three hundred fourteen million, one hundred twelve thousand, four hundred three".

Divisors: 1 19 127 2413 580735231 11033969389 73753374337 1401314112403