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14013210243 = 34671070081
BaseRepresentation
bin11010000110100000…
…01001111010000011
31100011121022211121210
431003100021322003
5212144340211433
610234303421203
71004155215234
oct150320117203
940147284553
1014013210243
115a4110129a
122870bb4803
1314242859a6
1496d15508b
15570392463
hex343409e83

14013210243 has 4 divisors (see below), whose sum is σ = 18684280328. Its totient is φ = 9342140160.

The previous prime is 14013210241. The next prime is 14013210247. The reversal of 14013210243 is 34201231041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34201231041 = 311400410347.

It is not a de Polignac number, because 14013210243 - 21 = 14013210241 is a prime.

It is a super-2 number, since 2×140132102432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14013210241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2335535038 + ... + 2335535043.

It is an arithmetic number, because the mean of its divisors is an integer number (4671070082).

Almost surely, 214013210243 is an apocalyptic number.

14013210243 is a deficient number, since it is larger than the sum of its proper divisors (4671070085).

14013210243 is an equidigital number, since it uses as much as digits as its factorization.

14013210243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4671070084.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 14013210243 its reverse (34201231041), we get a palindrome (48214441284).

The spelling of 14013210243 in words is "fourteen billion, thirteen million, two hundred ten thousand, two hundred forty-three".

Divisors: 1 3 4671070081 14013210243