Base | Representation |
---|---|
bin | 10100011001000101110… |
… | …001110100001111011011 |
3 | 11221222002002200002101011 |
4 | 110121011301310033123 |
5 | 140424410441303220 |
6 | 2551432341434351 |
7 | 203146156453144 |
oct | 24310561641733 |
9 | 4858062602334 |
10 | 1401330025435 |
11 | 4a03342a306a |
12 | 1a770670b9b7 |
13 | a21b6325582 |
14 | 4bb79104acb |
15 | 266b9cd165a |
hex | 14645c743db |
1401330025435 has 16 divisors (see below), whose sum is σ = 1831139056800. Its totient is φ = 1025437867776.
The previous prime is 1401330025409. The next prime is 1401330025441. The reversal of 1401330025435 is 5345200331041.
It is a cyclic number.
It is not a de Polignac number, because 1401330025435 - 221 = 1401327928283 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1401330025397 and 1401330025406.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 254322114 + ... + 254327623.
It is an arithmetic number, because the mean of its divisors is an integer number (114446191050).
Almost surely, 21401330025435 is an apocalyptic number.
1401330025435 is a deficient number, since it is larger than the sum of its proper divisors (429809031365).
1401330025435 is a wasteful number, since it uses less digits than its factorization.
1401330025435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 508649790.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 1401330025435 its reverse (5345200331041), we get a palindrome (6746530356476).
The spelling of 1401330025435 in words is "one trillion, four hundred one billion, three hundred thirty million, twenty-five thousand, four hundred thirty-five".
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