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14013431424353 is a prime number
BaseRepresentation
bin1100101111101100000110…
…0110100010010101100001
31211121200010010112000011202
43023323001212202111201
53314044001421034403
645445403113050545
72644302615520124
oct313730146422541
954550103460152
1014013431424353
114513076789599
1216a3a919b6a55
137a85cb81a61a
1436637a21c3bb
151947c516e688
hexcbec19a2561

14013431424353 has 2 divisors, whose sum is σ = 14013431424354. Its totient is φ = 14013431424352.

The previous prime is 14013431424329. The next prime is 14013431424371. The reversal of 14013431424353 is 35342413431041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10634955832384 + 3378475591969 = 3261128^2 + 1838063^2 .

It is a cyclic number.

It is not a de Polignac number, because 14013431424353 - 230 = 14012357682529 is a prime.

It is a super-2 number, since 2×140134314243532 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14013431424373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006715712176 + 7006715712177.

It is an arithmetic number, because the mean of its divisors is an integer number (7006715712177).

Almost surely, 214013431424353 is an apocalyptic number.

It is an amenable number.

14013431424353 is a deficient number, since it is larger than the sum of its proper divisors (1).

14013431424353 is an equidigital number, since it uses as much as digits as its factorization.

14013431424353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 207360, while the sum is 38.

Adding to 14013431424353 its reverse (35342413431041), we get a palindrome (49355844855394).

The spelling of 14013431424353 in words is "fourteen trillion, thirteen billion, four hundred thirty-one million, four hundred twenty-four thousand, three hundred fifty-three".