Base | Representation |
---|---|
bin | 10100011001001010001… |
… | …111110100110110101011 |
3 | 11221222021022202020200210 |
4 | 110121022033310312223 |
5 | 140430034140014011 |
6 | 2551444020432203 |
7 | 203151056652162 |
oct | 24311217646653 |
9 | 4858238666623 |
10 | 1401405001131 |
11 | 4a0372652453 |
12 | 1a7727848663 |
13 | a21c8a16aa5 |
14 | 4bb850603d9 |
15 | 266c16916a6 |
hex | 1464a3f4dab |
1401405001131 has 4 divisors (see below), whose sum is σ = 1868540001512. Its totient is φ = 934270000752.
The previous prime is 1401405001123. The next prime is 1401405001163. The reversal of 1401405001131 is 1311005041041.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1401405001131 - 23 = 1401405001123 is a prime.
It is a super-2 number, since 2×14014050011312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1401405001098 and 1401405001107.
It is not an unprimeable number, because it can be changed into a prime (1401405001121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233567500186 + ... + 233567500191.
It is an arithmetic number, because the mean of its divisors is an integer number (467135000378).
Almost surely, 21401405001131 is an apocalyptic number.
1401405001131 is a deficient number, since it is larger than the sum of its proper divisors (467135000381).
1401405001131 is an equidigital number, since it uses as much as digits as its factorization.
1401405001131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 467135000380.
The product of its (nonzero) digits is 240, while the sum is 21.
The spelling of 1401405001131 in words is "one trillion, four hundred one billion, four hundred five million, one thousand, one hundred thirty-one".
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