140140502104451 has 4 divisors (see below), whose sum is σ = 143122214915232. Its totient is φ = 137158789293672.

The previous prime is 140140502104439. The next prime is 140140502104571. The reversal of 140140502104451 is 154401205041041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140140502104451 is a prime.

It is a super-3 number, since 3×140140502104451³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140140502104411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1490856405320 + ... + 1490856405413.

It is an arithmetic number, because the mean of its divisors is an integer number (35780553728808).

Almost surely, 2^{140140502104451} is an apocalyptic number.

140140502104451 is a deficient number, since it is larger than the sum of its proper divisors (2981712810781).

140140502104451 is an equidigital number, since it uses as much as digits as its factorization.

140140502104451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2981712810780.

The product of its (nonzero) digits is 12800, while the sum is 32.

Adding to 140140502104451 its reverse (154401205041041), we get a palindrome (294541707145492).

The spelling of 140140502104451 in words is "one hundred forty trillion, one hundred forty billion, five hundred two million, one hundred four thousand, four hundred fifty-one".