1401440113 has 4 divisors (see below), whose sum is σ = 1401565428. Its totient is φ = 1401314800.

The previous prime is 1401440111. The next prime is 1401440123. The reversal of 1401440113 is 3110441041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 989228304 + 412211809 = 31452^2 + 20303^2 .

It is a cyclic number.

It is not a de Polignac number, because 1401440113 - 2¹ = 1401440111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1401440111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44038 + ... + 68863.

It is an arithmetic number, because the mean of its divisors is an integer number (350391357).

Almost surely, 2^1401440113 is an apocalyptic number.

It is an amenable number.

1401440113 is a deficient number, since it is larger than the sum of its proper divisors (125315).

1401440113 is a wasteful number, since it uses less digits than its factorization.

1401440113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 125314.

The product of its (nonzero) digits is 192, while the sum is 19.

The square root of 1401440113 is about 37435.8132407992. The cubic root of 1401440113 is about 1119.0723912253.

Adding to 1401440113 its reverse (3110441041), we get a palindrome (4511881154).

The spelling of 1401440113 in words is "one billion, four hundred one million, four hundred forty thousand, one hundred thirteen".