Base | Representation |
---|---|
bin | 11010000110101111… |
… | …00010000111010001 |
3 | 1100011201222002210021 |
4 | 31003113202013101 |
5 | 212200334110101 |
6 | 10234413103441 |
7 | 1004210522206 |
oct | 150327420721 |
9 | 40151862707 |
10 | 14015144401 |
11 | 5a42202475 |
12 | 2871787b81 |
13 | 14247b216b |
14 | 96d4d9cad |
15 | 5706255a1 |
hex | 3435e21d1 |
14015144401 has 4 divisors (see below), whose sum is σ = 14752783600. Its totient is φ = 13277505204.
The previous prime is 14015144393. The next prime is 14015144441. The reversal of 14015144401 is 10444151041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10444151041 = 19751 ⋅528791.
It is a cyclic number.
It is not a de Polignac number, because 14015144401 - 23 = 14015144393 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14015144441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 368819571 + ... + 368819608.
It is an arithmetic number, because the mean of its divisors is an integer number (3688195900).
Almost surely, 214015144401 is an apocalyptic number.
It is an amenable number.
14015144401 is a deficient number, since it is larger than the sum of its proper divisors (737639199).
14015144401 is an equidigital number, since it uses as much as digits as its factorization.
14015144401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 737639198.
The product of its (nonzero) digits is 1280, while the sum is 25.
Adding to 14015144401 its reverse (10444151041), we get a palindrome (24459295442).
The spelling of 14015144401 in words is "fourteen billion, fifteen million, one hundred forty-four thousand, four hundred one".
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