Base | Representation |
---|---|
bin | 10100011001010010000… |
… | …000101011111001111011 |
3 | 11221222121101211120121120 |
4 | 110121102000223321323 |
5 | 140430321011000133 |
6 | 2551504552240323 |
7 | 203154231030465 |
oct | 24312200537173 |
9 | 4858541746546 |
10 | 1401535250043 |
11 | 4a042a124385 |
12 | 1a77633a00a3 |
13 | a22199bb956 |
14 | 4bb98487135 |
15 | 266ccd1dab3 |
hex | 1465202be7b |
1401535250043 has 4 divisors (see below), whose sum is σ = 1868713666728. Its totient is φ = 934356833360.
The previous prime is 1401535250041. The next prime is 1401535250053. The reversal of 1401535250043 is 3400525351041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1401535250043 - 21 = 1401535250041 is a prime.
It is a super-2 number, since 2×14015352500432 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1401535249986 and 1401535250013.
It is not an unprimeable number, because it can be changed into a prime (1401535250041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233589208338 + ... + 233589208343.
It is an arithmetic number, because the mean of its divisors is an integer number (467178416682).
Almost surely, 21401535250043 is an apocalyptic number.
1401535250043 is a deficient number, since it is larger than the sum of its proper divisors (467178416685).
1401535250043 is an equidigital number, since it uses as much as digits as its factorization.
1401535250043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 467178416684.
The product of its (nonzero) digits is 36000, while the sum is 33.
The spelling of 1401535250043 in words is "one trillion, four hundred one billion, five hundred thirty-five million, two hundred fifty thousand, forty-three".
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