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14015421553 = 72002203079
BaseRepresentation
bin11010000110110001…
…00101110001110001
31100011202111011222011
431003120211301301
5212200421442203
610234423042521
71004213055220
oct150330456161
940152434864
1014015421553
115a42381721
1228718a0441
13142487b363
1496d56ccb7
1557067c76d
hex343625c71

14015421553 has 4 divisors (see below), whose sum is σ = 16017624640. Its totient is φ = 12013218468.

The previous prime is 14015421547. The next prime is 14015421587. The reversal of 14015421553 is 35512451041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14015421553 - 217 = 14015290481 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14015421593) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1001101533 + ... + 1001101546.

It is an arithmetic number, because the mean of its divisors is an integer number (4004406160).

Almost surely, 214015421553 is an apocalyptic number.

It is an amenable number.

14015421553 is a deficient number, since it is larger than the sum of its proper divisors (2002203087).

14015421553 is an equidigital number, since it uses as much as digits as its factorization.

14015421553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2002203086.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 14015421553 its reverse (35512451041), we get a palindrome (49527872594).

The spelling of 14015421553 in words is "fourteen billion, fifteen million, four hundred twenty-one thousand, five hundred fifty-three".

Divisors: 1 7 2002203079 14015421553