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1401553342153 = 4332594263771
BaseRepresentation
bin10100011001010011000…
…101101100111011001001
311221222122122212202022201
4110121103011230323021
5140430340123422103
62551510440120201
7203154540562246
oct24312305547311
94858578782281
101401553342153
114a0439361238
121a7769466061
13a2220684843
144bb9aa365cd
15266ce6e451d
hex1465316cec9

1401553342153 has 4 divisors (see below), whose sum is σ = 1434147605968. Its totient is φ = 1368959078340.

The previous prime is 1401553342151. The next prime is 1401553342243. The reversal of 1401553342153 is 3512433551041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1401553342153 - 21 = 1401553342151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1401553342151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16297131843 + ... + 16297131928.

It is an arithmetic number, because the mean of its divisors is an integer number (358536901492).

Almost surely, 21401553342153 is an apocalyptic number.

It is an amenable number.

1401553342153 is a deficient number, since it is larger than the sum of its proper divisors (32594263815).

1401553342153 is an equidigital number, since it uses as much as digits as its factorization.

1401553342153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32594263814.

The product of its (nonzero) digits is 108000, while the sum is 37.

Adding to 1401553342153 its reverse (3512433551041), we get a palindrome (4913986893194).

The spelling of 1401553342153 in words is "one trillion, four hundred one billion, five hundred fifty-three million, three hundred forty-two thousand, one hundred fifty-three".

Divisors: 1 43 32594263771 1401553342153