Base | Representation |
---|---|
bin | 1100101111110100000000… |
… | …0111111111110011110011 |
3 | 1211121212121001202101002211 |
4 | 3023331000013333303303 |
5 | 3314112323324000133 |
6 | 45450353501552551 |
7 | 2644406332261642 |
oct | 313750007776363 |
9 | 54555531671084 |
10 | 14015554125043 |
11 | 4513a65a11a89 |
12 | 16a4384875757 |
13 | 7a8879525c33 |
14 | 3664dc0d7359 |
15 | 19489b6bcbcd |
hex | cbf401ffcf3 |
14015554125043 has 2 divisors, whose sum is σ = 14015554125044. Its totient is φ = 14015554125042.
The previous prime is 14015554125031. The next prime is 14015554125091. The reversal of 14015554125043 is 34052145551041.
It is a weak prime.
It is an emirp because it is prime and its reverse (34052145551041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14015554125043 - 221 = 14015552027891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14015554124987 and 14015554125005.
It is not a weakly prime, because it can be changed into another prime (14015554125343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7007777062521 + 7007777062522.
It is an arithmetic number, because the mean of its divisors is an integer number (7007777062522).
Almost surely, 214015554125043 is an apocalyptic number.
14015554125043 is a deficient number, since it is larger than the sum of its proper divisors (1).
14015554125043 is an equidigital number, since it uses as much as digits as its factorization.
14015554125043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240000, while the sum is 40.
Adding to 14015554125043 its reverse (34052145551041), we get a palindrome (48067699676084).
The spelling of 14015554125043 in words is "fourteen trillion, fifteen billion, five hundred fifty-four million, one hundred twenty-five thousand, forty-three".
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