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140175531775057 is a prime number
BaseRepresentation
bin11111110111110100101000…
…110001110001010001010001
3200101022122112211020121112011
4133313310220301301101101
5121333113442113300212
61214043430022102521
741345230231536232
oct3767645061612121
9611278484217464
10140175531775057
1140734122355939
121387ab59b7aa41
13602a65a72535c
1426887638cd089
1511314497d14a7
hex7f7d28c71451

140175531775057 has 2 divisors, whose sum is σ = 140175531775058. Its totient is φ = 140175531775056.

The previous prime is 140175531774973. The next prime is 140175531775061. The reversal of 140175531775057 is 750577135571041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121762198537281 + 18413333237776 = 11034591^2 + 4291076^2 .

It is a cyclic number.

It is not a de Polignac number, because 140175531775057 - 223 = 140175523386449 is a prime.

It is a super-2 number, since 2×1401755317750572 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140175531774992 and 140175531775010.

It is not a weakly prime, because it can be changed into another prime (140175531775087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70087765887528 + 70087765887529.

It is an arithmetic number, because the mean of its divisors is an integer number (70087765887529).

Almost surely, 2140175531775057 is an apocalyptic number.

It is an amenable number.

140175531775057 is a deficient number, since it is larger than the sum of its proper divisors (1).

140175531775057 is an equidigital number, since it uses as much as digits as its factorization.

140175531775057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18007500, while the sum is 58.

The spelling of 140175531775057 in words is "one hundred forty trillion, one hundred seventy-five billion, five hundred thirty-one million, seven hundred seventy-five thousand, fifty-seven".