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14018850433 = 72002692919
BaseRepresentation
bin11010000111001011…
…01010111010000001
31100011222221101111201
431003211222322001
5212202311203213
610235024341201
71004254156030
oct150345527201
940158841451
1014018850433
115a44303905
122872a74801
1314254abc93
1496dbc2717
15570b086dd
hex34396ae81

14018850433 has 4 divisors (see below), whose sum is σ = 16021543360. Its totient is φ = 12016157508.

The previous prime is 14018850409. The next prime is 14018850457. The reversal of 14018850433 is 33405881041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (14018850409) and next prime (14018850457).

It is a cyclic number.

It is not a de Polignac number, because 14018850433 - 25 = 14018850401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14018850392 and 14018850401.

It is not an unprimeable number, because it can be changed into a prime (14018850133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1001346453 + ... + 1001346466.

It is an arithmetic number, because the mean of its divisors is an integer number (4005385840).

Almost surely, 214018850433 is an apocalyptic number.

It is an amenable number.

14018850433 is a deficient number, since it is larger than the sum of its proper divisors (2002692927).

14018850433 is an equidigital number, since it uses as much as digits as its factorization.

14018850433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2002692926.

The product of its (nonzero) digits is 46080, while the sum is 37.

The spelling of 14018850433 in words is "fourteen billion, eighteen million, eight hundred fifty thousand, four hundred thirty-three".

Divisors: 1 7 2002692919 14018850433