Base | Representation |
---|---|
bin | 1100110000000011111000… |
… | …1010111110010110000011 |
3 | 1211122021121002211020010210 |
4 | 3030000332022332112003 |
5 | 3314200040434141324 |
6 | 45452340435325203 |
7 | 2644620055313316 |
oct | 314007612762603 |
9 | 54567532736123 |
10 | 14019816318339 |
11 | 45158528a7987 |
12 | 16a5174150803 |
13 | 7a90a8568cc0 |
14 | 3667c41bc97d |
15 | 194a4a984d29 |
hex | cc03e2be583 |
14019816318339 has 32 divisors (see below), whose sum is σ = 20485959939648. Its totient is φ = 8475806016000.
The previous prime is 14019816318283. The next prime is 14019816318371. The reversal of 14019816318339 is 93381361891041.
It is not a de Polignac number, because 14019816318339 - 215 = 14019816285571 is a prime.
It is a super-3 number, since 3×140198163183393 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (14019816313339) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1635852 + ... + 5542169.
It is an arithmetic number, because the mean of its divisors is an integer number (640186248114).
Almost surely, 214019816318339 is an apocalyptic number.
14019816318339 is a deficient number, since it is larger than the sum of its proper divisors (6466143621309).
14019816318339 is a wasteful number, since it uses less digits than its factorization.
14019816318339 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7178919.
The product of its (nonzero) digits is 3359232, while the sum is 57.
The spelling of 14019816318339 in words is "fourteen trillion, nineteen billion, eight hundred sixteen million, three hundred eighteen thousand, three hundred thirty-nine".
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