Base | Representation |
---|---|
bin | 11010000111011101… |
… | …00111011001111011 |
3 | 1100012011100112011212 |
4 | 31003232213121323 |
5 | 212203411223022 |
6 | 10235150513335 |
7 | 1004313123443 |
oct | 150356473173 |
9 | 40164315155 |
10 | 14021195387 |
11 | 5a45665691 |
12 | 287380584b |
13 | 1425b20424 |
14 | 970233123 |
15 | 570e1d3e2 |
hex | 343ba767b |
14021195387 has 4 divisors (see below), whose sum is σ = 14048005080. Its totient is φ = 13994385696.
The previous prime is 14021195381. The next prime is 14021195411. The reversal of 14021195387 is 78359112041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14021195387 - 24 = 14021195371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14021195381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13404062 + ... + 13405107.
It is an arithmetic number, because the mean of its divisors is an integer number (3512001270).
Almost surely, 214021195387 is an apocalyptic number.
14021195387 is a deficient number, since it is larger than the sum of its proper divisors (26809693).
14021195387 is an equidigital number, since it uses as much as digits as its factorization.
14021195387 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26809692.
The product of its (nonzero) digits is 60480, while the sum is 41.
The spelling of 14021195387 in words is "fourteen billion, twenty-one million, one hundred ninety-five thousand, three hundred eighty-seven".
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