Base | Representation |
---|---|
bin | 11111111000010111101000… |
… | …101100010110111001010011 |
3 | 200101110020112210210022002111 |
4 | 133320113220230112321103 |
5 | 121334222422444221042 |
6 | 1214113003014130151 |
7 | 41351030415441205 |
oct | 3770275054267123 |
9 | 611406483708074 |
10 | 140213111320147 |
11 | 40749056aa0318 |
12 | 138862a7350957 |
13 | 60310691a9778 |
14 | 268a4ca834775 |
15 | 11323e8a51517 |
hex | 7f85e8b16e53 |
140213111320147 has 2 divisors, whose sum is σ = 140213111320148. Its totient is φ = 140213111320146.
The previous prime is 140213111320133. The next prime is 140213111320171. The reversal of 140213111320147 is 741023111312041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140213111320147 - 27 = 140213111320019 is a prime.
It is not a weakly prime, because it can be changed into another prime (140213111320187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70106555660073 + 70106555660074.
It is an arithmetic number, because the mean of its divisors is an integer number (70106555660074).
Almost surely, 2140213111320147 is an apocalyptic number.
140213111320147 is a deficient number, since it is larger than the sum of its proper divisors (1).
140213111320147 is an equidigital number, since it uses as much as digits as its factorization.
140213111320147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 31.
Adding to 140213111320147 its reverse (741023111312041), we get a palindrome (881236222632188).
The spelling of 140213111320147 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred eleven million, three hundred twenty thousand, one hundred forty-seven".
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