140213111498843 has 2 divisors, whose sum is σ = 140213111498844. Its totient is φ = 140213111498842.

The previous prime is 140213111498821. The next prime is 140213111498861. The reversal of 140213111498843 is 348894111312041.

It is a strong prime.

It is an emirp because it is prime and its reverse (348894111312041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140213111498843 - 2⁴⁰ = 139113599871067 is a prime.

It is a super-3 number, since 3×140213111498843³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140213111498791 and 140213111498800.

It is not a weakly prime, because it can be changed into another prime (140213111498893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70106555749421 + 70106555749422.

It is an arithmetic number, because the mean of its divisors is an integer number (70106555749422).

Almost surely, 2^{140213111498843} is an apocalyptic number.

140213111498843 is a deficient number, since it is larger than the sum of its proper divisors (1).

140213111498843 is an equidigital number, since it uses as much as digits as its factorization.

140213111498843 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 663552, while the sum is 50.

The spelling of 140213111498843 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred eleven million, four hundred ninety-eight thousand, eight hundred forty-three".