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140213122400113 = 764131248745799
BaseRepresentation
bin11111111000010111101001…
…010110100111111101110001
3200101110020120120122012221121
4133320113221112213331301
5121334222433313300423
61214113004051422241
741351030611556260
oct3770275126477561
9611406516565847
10140213122400113
1140749062278914
12138862aabb4981
13603106b588a69
14268a4cc0ba5d7
1511323e99de45d
hex7f85e95a7f71

140213122400113 has 8 divisors (see below), whose sum is σ = 160493558428800. Its totient is φ = 119995183864320.

The previous prime is 140213122400047. The next prime is 140213122400189. The reversal of 140213122400113 is 311004221312041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 140213122400113 - 217 = 140213122269041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140213122400213) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15624368413 + ... + 15624377386.

It is an arithmetic number, because the mean of its divisors is an integer number (20061694803600).

Almost surely, 2140213122400113 is an apocalyptic number.

It is an amenable number.

140213122400113 is a deficient number, since it is larger than the sum of its proper divisors (20280436028687).

140213122400113 is an equidigital number, since it uses as much as digits as its factorization.

140213122400113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31248746447.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 140213122400113 its reverse (311004221312041), we get a palindrome (451217343712154).

The spelling of 140213122400113 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred twenty-two million, four hundred thousand, one hundred thirteen".

Divisors: 1 7 641 4487 31248745799 218741220593 20030446057159 140213122400113