14021401440433 has 4 divisors (see below), whose sum is σ = 14023842923008. Its totient is φ = 14018959957860.

The previous prime is 14021401440421. The next prime is 14021401440439. The reversal of 14021401440433 is 33404410412041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14021401440433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14021401440395 and 14021401440404.

It is not an unprimeable number, because it can be changed into a prime (14021401440439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1220732673 + ... + 1220744158.

It is an arithmetic number, because the mean of its divisors is an integer number (3505960730752).

Almost surely, 2^{14021401440433} is an apocalyptic number.

It is an amenable number.

14021401440433 is a deficient number, since it is larger than the sum of its proper divisors (2441482575).

14021401440433 is an equidigital number, since it uses as much as digits as its factorization.

14021401440433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2441482574.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 14021401440433 its reverse (33404410412041), we get a palindrome (47425811852474).

The spelling of 14021401440433 in words is "fourteen trillion, twenty-one billion, four hundred one million, four hundred forty thousand, four hundred thirty-three".