140214121131034 has 4 divisors (see below), whose sum is σ = 210321181696554. Its totient is φ = 70107060565516.

The previous prime is 140214121130999. The next prime is 140214121131127. The reversal of 140214121131034 is 430131121412041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 112200950325025 + 28013170806009 = 10592495^2 + 5292747^2 .

It is a junction number, because it is equal to n+sod(n) for n = 140214121130993 and 140214121131011.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35053530282757 + ... + 35053530282760.

Almost surely, 2^{140214121131034} is an apocalyptic number.

140214121131034 is a deficient number, since it is larger than the sum of its proper divisors (70107060565520).

140214121131034 is an equidigital number, since it uses as much as digits as its factorization.

140214121131034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70107060565519.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 140214121131034 its reverse (430131121412041), we get a palindrome (570345242543075).

The spelling of 140214121131034 in words is "one hundred forty trillion, two hundred fourteen billion, one hundred twenty-one million, one hundred thirty-one thousand, thirty-four".