140214131210401 has 8 divisors (see below), whose sum is σ = 140501738463840. Its totient is φ = 139926660692352.

The previous prime is 140214131210381. The next prime is 140214131210539. The reversal of 140214131210401 is 104012131412041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 140214131210401 - 2¹¹ = 140214131208353 is a prime.

It is a super-3 number, since 3×140214131210401³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140214131610401) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32130736 + ... + 36232753.

It is an arithmetic number, because the mean of its divisors is an integer number (17562717307980).

Almost surely, 2^{140214131210401} is an apocalyptic number.

It is an amenable number.

140214131210401 is a deficient number, since it is larger than the sum of its proper divisors (287607253439).

140214131210401 is an equidigital number, since it uses as much as digits as its factorization.

140214131210401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68367695.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 140214131210401 its reverse (104012131412041), we get a palindrome (244226262622442).

The spelling of 140214131210401 in words is "one hundred forty trillion, two hundred fourteen billion, one hundred thirty-one million, two hundred ten thousand, four hundred one".